This is true, we don't have any other name for it.



I found a site with examples of the calculations I remembered, just so I don't look completely crazy. This one involves someone who mixed beer & spirits




http://www.brautbar.net/article-alcohol-toxicity.html




Example 3
A man weighing 220 pounds started drinking at 5:00 p.m. and continued to drink until 1:00 a.m. During this time he neglected to eat any food. During the course of the evening he consumed seven 16 ounce beers, and ten 1 ounce shots of whisky 86 proof. At 3:00 a.m. he was involved in an automobile accident. At 4:00 a.m. a blood sample was drawn for alcohol content. The question is, how do we calculate the BAC at the time the blood was drawn. First of all we will calculate the BAC from beers which should be calculated at a body weight of 220 pounds, 150 divided by 220 times 4 divided by 50 times 112 times 0.025% which is 0.153% from beer, and from whisky 150 divided by 220 times 43 divided by 50 times 10 times 0.025% equals 0.147, total BAC from beer and whisky is 0.3% using the formula 150/a x B/150 x C x 0.025 = D. The elapsed time between the first drink which was at 5:00 p.m. and the blood sample was drawn at 4:00 a.m. is 11 hours. The amount of alcohol dissipated during this time is estimated at a range of dissipation rate of 0.300 minus 0.165 which equals 0.135 or alternatively 0.300 minus 0.198 which equals 0.102% or 0.300 minus 0.22 which equals 0.08%. (One has to use the low, high and average dissipation rate, because it is individualized and unknown for a given individual, and therefore BAC dissipation using the average dissipation rate is desirable). The formula here is: BAC - (Dissipation rate x number of hours elapsed), which is 0.3 - 0.165+0.135%. The median figure of 0.135% is the reasonable one